[C#] 利用 LINQ 解析 XML 至 POCO

menu_config.xml

<?xml version="1.0" encoding="utf-8"?>
  <menu_config>
    <menu title="文章管理" url="~/Article" target="" allow="">
        <submenu title="列表" url="~/Article/list" allow="" />
        <submenu />
        <submenu title="新增" url="~/Article/add" allow="" />
    </menu>
    <menu />
    <menu title="帳號管理" url="~/Admin" />
  </menu_config>

//using System.Collections.Generic;
//using System.IO;
//using System.Linq;
//using System.Xml.Linq;
//using System.Text;

public class MenuDataModel
{
    /*POCO 資料欄位*/
    public string Title { get; set; }
    public string Url { get; set; }
    public string Target { get; set; }
    public string Allow { get; set; }
    public string Icon { get; set; }
    public List<MenuDataModel> Submenu { get; set; }

    /*取得資料清單*/
    public static List<MenuDataModel> GetList(string menuConfigPath)
    {
        /*讀取 XML 檔案*/
        var xmlContent = File.ReadAllText(menuConfigPath, Encoding.UTF8);
        var menuDocument = XDocument.Parse(xmlContent);

        /*利用 LINQ 轉成 POCO*/
        return menuDocument.Root.Elements("menu")
        .Select(menu => new MenuDataModel
        {
            /*取得 Element 上的 Attribute*/
            Title   = (string) menu.Attribute("title"),
            Url     = (string) menu.Attribute("url"),
            Target  = (string) menu.Attribute("target"),
            Icon    = (string) menu.Attribute("icon") ?? "Item",
            Allow   = (string) menu.Attribute("allow"),

            /*取得子層級 Element 上的 Attribute*/
            Submenu = menu.Elements("submenu")
            .Select(sub => new MenuDataModel
            {
                Title   = (string) sub.Attribute("title"),
                Url     = (string) sub.Attribute("url"),
                Target  = (string) sub.Attribute("target"),
                Icon    = (string) sub.Attribute("icon") ?? "Item",
                Allow   = (string) sub.Attribute("allow"),
            }).ToList(),
        }).ToList();
    }
}


void Main()
{
    var path = @"D:\menu_config.xml";

    List<MenuDataModel> list =  MenuDataModel.GetList(path);

    list.Dump();
}